India won the second T20 against Australia by six wickets

Nagpur , dt. 23

After Akshar Patel took two wickets for 13 runs, Rohit Sharma hit an unbeaten 46 off 20 balls with 4 fours and 4 sixes as India beat Australia by six wickets with four balls to spare in the second T20I. In Nagpur, the T20 was played 8-8 overs as the field was flooded due to rain. In which Australia achieved the target of 91 to win by losing four wickets in 7.2 overs. With this, India tied the series 1-1. Now the final T20 will be played on 25th September on Sunday.

Chasing a target of 91 to win, India scored 39 runs in just 17 balls. Rahul was a victim of Zampa for 10 runs. After that, Kohli gave the wicket to Zampa for 11 runs and Suryakumar for 0. Hardik was also dismissed for 9 runs. However, Rohit played an unbeaten captain's innings of 46 runs. While Dinesh Karthik scored 10 unbeaten runs with sixes and fours in two balls.

Earlier, after winning the toss, India chose to field first. Green was run out for fifteen runs. While Maxwell 0 and David 2 were dismissed by Akshar Patel's bowling. Matthew Wade scored an unbeaten 43 off 20 balls with 4 fours and 3 sixes. While Finch scored 31 runs in 15 balls with 4 fours and 1 six. His wicket was taken by Bumrah. Akshar got two wickets for 13 runs and Bumrah got 1 wicket for 23 runs.